document.write( "Question 895168: Please help me to solve this equation\r
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\n" ); document.write( "√(2x²+5x-2) - √(2x²+5x-9) = 1 are \n" ); document.write( "

Algebra.Com's Answer #542626 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Isolate one of the terms with a radical:\r\n" );
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document.write( "Square both sides:\r\n" );
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document.write( "To make things a little easier to see\r\n" );
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document.write( "let  and let  \r\n" );
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document.write( "Then we have\r\n" );
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document.write( "Since we let  and let \r\n" );
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document.write( "then  and  \r\n" );
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document.write( "So\r\n" );
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document.write( "becomes\r\n" );
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document.write( "Isolate the radical term (the 2x²'s and the 5x's will cancel)\r\n" );
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document.write( "Divide both sides by 2\r\n" );
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document.write( "Square both sides:\r\n" );
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document.write( "Get 0 on the left:\r\n" );
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document.write( "Factor the right side:\r\n" );
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document.write( "Use the zero-factor property:\r\n" );
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document.write( "2x+9=0;     x-2=0\r\n" );
document.write( "  2x=-9       x=2\r\n" );
document.write( "   x=\r\n" );
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document.write( "But we must check in the original equation, since radical \r\n" );
document.write( "equations often have extraneous answers:\r\n" );
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document.write( "Checking \r\n" );
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document.write( "So  is a solution.\r\n" );
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document.write( "Checking \r\n" );
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document.write( "So x=2 is also a solution.\r\n" );
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document.write( "Edwin

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