document.write( "Question 894992: 2/3 . (y + 6) y=3 \n" ); document.write( "
Algebra.Com's Answer #542612 by Fombitz(32388)\"\" \"About 
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\"%28y%2B6%29y=3\"
\n" ); document.write( "\"y%5E2%2B6y=3\"
\n" ); document.write( "\"y%5E2%2B6y%2B9=3%2B9\"
\n" ); document.write( "\"%28y%2B3%29%5E2=12\"
\n" ); document.write( "\"y%2B3=0+%2B-+sqrt%2812%29\"
\n" ); document.write( "\"y=-3+%2B-+2sqrt%283%29\"
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