document.write( "Question 895141: 2^(x-1)+2^(x-1)=2860 find the value of x ? (Surds and indices) \n" ); document.write( "
Algebra.Com's Answer #542586 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
2^(x-1) + 2^(x-1) = 2*2^(x-1)\r
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\n" ); document.write( "\n" ); document.write( "your formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "2*2^(x-1) = 2860\r
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\n" ); document.write( "\n" ); document.write( "divide both sides by 2 to get:\r
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\n" ); document.write( "\n" ); document.write( "2^(x-1) = 1430\r
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\n" ); document.write( "\n" ); document.write( "take log of both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "log(2^(x-1) = log(1430\r
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\n" ); document.write( "\n" ); document.write( "since log(2^(x-1)) = (x-1)*log(2), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "(x-1)*log(2) = log(1430)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides by log(2) to get:\r
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\n" ); document.write( "\n" ); document.write( "x-1 = (1og(1430)/log(2)\r
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\n" ); document.write( "\n" ); document.write( "add 1 to both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "x = log(1430)/log(2) + 1\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 11.48179...\r
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\n" ); document.write( "\n" ); document.write( "confirm by going back to the original equation to get:\r
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\n" ); document.write( "\n" ); document.write( "2^(11.28179... - 1) + 2^(11.28179... - 1) = 2860\r
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\n" ); document.write( "\n" ); document.write( "solve to get:\r
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\n" ); document.write( "\n" ); document.write( "2860 = 2860.\r
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\n" ); document.write( "\n" ); document.write( "your answer is that x = 11.48179943...\r
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\n" ); document.write( "\n" ); document.write( "the value for x was internally stored in my calculator.\r
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\n" ); document.write( "\n" ); document.write( "all calculations were done using the stored number.\r
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