document.write( "Question 75591: 2 planes leave Newyork AT 10am, one heading for Europe at 600mph and one heading in the opposite direction at 150mph. At what time will they be 900 miles apart? \n" ); document.write( "
Algebra.Com's Answer #54258 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
Let the planes be 900 miles apart after 't' hours from start.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"SPEED+=+DISTANCE%2FTIME\" or \"DISTANCE+=+SPEEDxTIME\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In 't' hrs. the first plane travels = \"600%2At\" miles.
\n" ); document.write( "In 't' hrs. the second plane travels = \"150%2At\" miles.
\n" ); document.write( "After 't' hours the distance between the two planes flying in opposite directions = (600t + 150t) = 750t mph.
\n" ); document.write( "When, this distance is 900 miles,
\n" ); document.write( "\"750t+=+900\"
\n" ); document.write( "\"t+=+900%2F750+=+6%2F5\"
\n" ); document.write( "So the reqd. time vis t = 1.2 hrs. = 1.2*60 min = 72 min = 1 hr 12 min.
\n" ); document.write( "Thus the planes will be 900 miles apart at 11:12 am.
\n" ); document.write( "
\n" );