document.write( "Question 895054: Tom can run 5 miles in 1 hour less than the time required for David to run 4 miles. If tom is 4 mph faster than David, how many hours does each man run? \n" ); document.write( "
Algebra.Com's Answer #542565 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Tom can run 5 miles in 1 hour less than the time required for David to run 4 miles. If tom is 4 mph faster than David, how many hours does each man run? \n" ); document.write( "*** \n" ); document.write( "let x=David's speed \n" ); document.write( "x+4=Tom's speed \n" ); document.write( "Travel time=Distance/speed \n" ); document.write( ".. \n" ); document.write( "(4/x)-5/(x+4))=1 \n" ); document.write( "lcd:x(x+4) \n" ); document.write( "4(x+4)-5x=x(x+4) \n" ); document.write( "4x+16-5x=x^2+4x \n" ); document.write( "x^2+5x-16 \n" ); document.write( "solve for x by quadratic formula: \n" ); document.write( " \n" ); document.write( "a=1, b=-5, c=-16 \n" ); document.write( "ans: \n" ); document.write( "x≈-7.2 (reject) \n" ); document.write( "or \n" ); document.write( "x≈2.2 \n" ); document.write( "x+4≈6.2 \n" ); document.write( ".. \n" ); document.write( "4/2.2≈1.8 hrs \n" ); document.write( "5/6.2≈0.8 hrs \n" ); document.write( "how many hours does each man run? \n" ); document.write( "Tom:0.8 \n" ); document.write( "David:1.8\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |