document.write( "Question 895036: The supplement of an angle y measures 10x+4 and the complement of the angle measures 4x. What is the measure of angle y? The answer is 32.7 degrees. I don't know how they came to that answer.\r
\n" ); document.write( "\n" ); document.write( "-I tried taking the 10x+4-y=180. But after subtracting and getting like numbers on their respective sides I end up with x-y=17.6. This is where I'm stuck. The back of the book states that the answer is supposed to be 32.7 degrees. ??? Help Please!!!
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Algebra.Com's Answer #542558 by MathTherapy(10552)\"\" \"About 
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The supplement of an angle y measures 10x+4 and the complement of the angle measures 4x. What is the measure of angle y? The answer is 32.7 degrees. I don't know how they came to that answer.\r
\n" ); document.write( "\n" ); document.write( "-I tried taking the 10x+4-y=180. But after subtracting and getting like numbers on their respective sides I end up with x-y=17.6. This is where I'm stuck. The back of the book states that the answer is supposed to be 32.7 degrees. ??? Help Please!!!
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\n" ); document.write( "Since angle y’s supplement is: 10x + 4, then y = 180 – (10x + 4), or y = 180 – 10x – 4, or y = 176 – 10x
\n" ); document.write( "Since angle y’s complement is: 4x, then y = 90 – 4x
\n" ); document.write( "Since y = 176 – 10x, and y also = 90 – 4x, then we can say that:
\n" ); document.write( "176 – 10x = 90 – 4x
\n" ); document.write( "– 10x + 4x = 90 – 176
\n" ); document.write( "- 6x = - 86
\n" ); document.write( "x = \"%28-+86%29%2F-+6\", or \"43%2F3\", or \"14%261%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Since \"x+=+43%2F3\", then this value can be substituted in any of the y-equations to determine the value of y.
\n" ); document.write( "Using the 2nd y-equation (easier of the 2): y = 90 – 4x, we now have:
\n" ); document.write( "\"y+=+90+-+4%2843%2F3%29\" ------ Substituting \"43%2F3\" for x
\n" ); document.write( "\"y+=+90+-+172%2F3\"
\n" ); document.write( "\"y+=+270%2F3+-+172%2F3\"
\n" ); document.write( "y = \"98%2F3\", or \"y+=+32%262%2F3\", or y = 32.66666 ≈ \"highlight_green%2832.7%5Eo%29\" \n" ); document.write( "
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