document.write( "Question 895070: A quarter mile running track has the formula for the inside perimeter as P=2πr+2x.
\n" ); document.write( "a)Solve the perimeter formula for r.
\n" ); document.write( "b)For a quarter mile track, P=440 yards. Find r when x=75 yards, 100 yards, 120 yards, and 150 yards.
\n" ); document.write( "c)What are the greatest and least possible values of r if P=440 yards? Explain how you found the values, and sketch the track according to each extreme value.
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Algebra.Com's Answer #542535 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
To answer (a) and (b), you simply have r as a factor in only one term, so solving for r is simple. For (b), you just substitute the values and evaluate ------ r.\r
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\n" ); document.write( "\n" ); document.write( "\"P=2pi%2Ar%2B2x\"
\n" ); document.write( "\"P-2x=2pi%2Ar\"
\n" ); document.write( "\"highlight%28%28P-2x%29%2F%282pi%29=r%29\"\r
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\n" ); document.write( "\n" ); document.write( "Question part (c) is not complicated. P or r is a linear function of r or P. Same with r and x. Think about the formula given, and you understand that x is the straight length of the track. If the track has NO straight section to length then you simply have a circular track, and x=0. Clear, right? r is what now? \r
\n" ); document.write( "\n" ); document.write( "Look again: \"P=2pi%2Ar%2B2x\", and if x becomes zero, then
\n" ); document.write( "\"P=2pi%2Ar%2B2%2A0\"
\n" ); document.write( "\"P=2pi%2Ar\"
\n" ); document.write( "\"r=P%2F%282pi%29\"
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