document.write( "Question 894846: a.Estimate a value of Z that the area under the standard normal curve to the
\n" ); document.write( " right of z is 0.25.
\n" ); document.write( "b find the area under the standard normal curve between z1= -2.50 and z2 = -1.25
\n" ); document.write( "c. estimate the value of z such that the area under the standard normal curve
\n" ); document.write( " between -z and z is 0.70.
\n" ); document.write( "d. for the standard normal curve find the value of z such that the area to
\n" ); document.write( " the left of -z plus the area to the right of z is 0.05.\r
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Algebra.Com's Answer #542518 by stanbon(75887)\"\" \"About 
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a.Estimate a value of Z that the area under the standard normal curve to the
\n" ); document.write( "right of z is 0.25.
\n" ); document.write( "P(z > 0.25) = normalcdf(0.25,100) = 0.4013
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\n" ); document.write( " b find the area under the standard normal curve between z1= -2.50 and z2 = -1.25
\n" ); document.write( "P(-2.5 < z < -1.25) = normalcdf(-2.5,-1.25) = 0.0994
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\n" ); document.write( " c. estimate the value of z such that the area under the standard normal curve
\n" ); document.write( "between -z and z is 0.70.
\n" ); document.write( "Note: 0.35 must be on the left side of the mean.
\n" ); document.write( "That leaves a left tail of 0.15
\n" ); document.write( "invNorm(0.15) = -1.036
\n" ); document.write( "Answer:: z = 1.036
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\n" ); document.write( " d. for the standard normal curve find the value of z such that the area to
\n" ); document.write( "the left of -z plus the area to the right of z is 0.05.
\n" ); document.write( "Ans: invNorm(0.05) = -1.645
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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