document.write( "Question 894905: The length of stay for patients in some 20 hospitals was 3.8 days with a standard deviation of 1.2 days. Can you determine the confidence interval for the length of stay?\r
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Algebra.Com's Answer #542483 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of stay for patients in some 20 hospitals was 3.8 days with a standard deviation of 1.2 days. Can you determine the confidence interval for the length of stay? \n" ); document.write( " a=0.1 \n" ); document.write( "------------ \n" ); document.write( "x-bar = 3.8 \n" ); document.write( "ME = z*s/sqrt(n) = 2.5758*1.2/sqrt(20) = 0.6912 \n" ); document.write( "----- \n" ); document.write( "99% CI:: 3.8-0.6912 < u < 3.8+0.6912 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |