document.write( "Question 894973: Abigail is 28 years younger than her mother Bethany. the sum of their ages is 66 . how old is each now \n" ); document.write( "
Algebra.Com's Answer #542466 by harpazo(655)![]() ![]() You can put this solution on YOUR website! Let A = Abigail\r \n" ); document.write( "\n" ); document.write( "Let B = Bethany\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = B - 28 \n" ); document.write( "A + B = 66\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B - 28 + B = 66\r \n" ); document.write( "\n" ); document.write( "2B - 28 = 66\r \n" ); document.write( "\n" ); document.write( "2B = 66 + 28\r \n" ); document.write( "\n" ); document.write( "2B = 94\r \n" ); document.write( "\n" ); document.write( "B = 94/2\r \n" ); document.write( "\n" ); document.write( "B = 47.\r \n" ); document.write( "\n" ); document.write( "Bethany is 47.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How old is Abigail?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Think for a minute.\r \n" ); document.write( "\n" ); document.write( "If I subtract 47 from the total of their ages, I will know Abigail's age, right?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, Abigail is 66 - 47 or 19.\r \n" ); document.write( "\n" ); document.write( "Abigail is 19 and Bethany is 47.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |