document.write( "Question 894973: Abigail is 28 years younger than her mother Bethany. the sum of their ages is 66 . how old is each now \n" ); document.write( "
Algebra.Com's Answer #542466 by harpazo(655)\"\" \"About 
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Let A = Abigail\r
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\n" ); document.write( "\n" ); document.write( "A = B - 28
\n" ); document.write( "A + B = 66\r
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\n" ); document.write( "\n" ); document.write( "B - 28 + B = 66\r
\n" ); document.write( "\n" ); document.write( "2B - 28 = 66\r
\n" ); document.write( "\n" ); document.write( "2B = 66 + 28\r
\n" ); document.write( "\n" ); document.write( "2B = 94\r
\n" ); document.write( "\n" ); document.write( "B = 94/2\r
\n" ); document.write( "\n" ); document.write( "B = 47.\r
\n" ); document.write( "\n" ); document.write( "Bethany is 47.\r
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\n" ); document.write( "\n" ); document.write( "How old is Abigail?\r
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\n" ); document.write( "\n" ); document.write( "Think for a minute.\r
\n" ); document.write( "\n" ); document.write( "If I subtract 47 from the total of their ages, I will know Abigail's age, right?\r
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\n" ); document.write( "\n" ); document.write( "So, Abigail is 66 - 47 or 19.\r
\n" ); document.write( "\n" ); document.write( "Abigail is 19 and Bethany is 47.\r
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