document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894920>Question 894920</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Renee and Betsy decide to have a 10 mile race. Renee can run an average speed of 12 miles per hour while Betsy can run at an average speed of 10 miles per hour. Renee decides to give Betsy a head start of 9 minutes. How many minutes will it take Renee to catch up with Betsy? Can you solve the problem for me please with also showing me the way to do it </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #542435 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=542435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Renee and Betsy decide to have a 10 mile race.<BR>\n" );
document.write( " Renee can run an average speed of 12 miles per hour while Betsy can run at an average speed of 10 miles per hour.<BR>\n" );
document.write( " Renee decides to give Betsy a head start of 9 minutes.<BR>\n" );
document.write( " How many minutes will it take Renee to catch up with Betsy?<BR>\n" );
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document.write( "Since we are dealing in minutes here, we want to have their speeds in mi/min<BR>\n" );
document.write( "R: 12/60 = 1/5 mi/min<BR>\n" );
document.write( "B: 10/60 = 1/6 mi/min<BR>\n" );
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document.write( "let t = the running time of Renee when she catches Betsy (in minutes)<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(t+9) = running time of Betsy<BR>\n" );
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document.write( "When R catches B they will have run the same distance<BR>\n" );
document.write( "write a distance equation; dist = speed * time<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F5 ALIGN=MIDDLE  ALT=\"1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F6 ALIGN=MIDDLE  ALT=\"1%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >(t+9)<BR>\n" );
document.write( "multiply both sides by 30, cancel the denominators and you have<BR>\n" );
document.write( "6t = 5(t+9)<BR>\n" );
document.write( "6t = 5t + 45<BR>\n" );
document.write( "6t - 5t = 45<BR>\n" );
document.write( "t = 45 min for R to catch B<BR>\n" );
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document.write( ";<BR>\n" );
document.write( "We can confirm this find the actual distance when this occurs (should be equal)<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F5 ALIGN=MIDDLE  ALT=\"1%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >(45) = 9 mi<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F6 ALIGN=MIDDLE  ALT=\"1%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >(45+9) = 9 mi<BR>\n" );
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document.write( "Did I make this understandable to you? C </SPAN>\n" );
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