document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894881>Question 894881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi. I need help with mixtures I went over this topic last year in school but completely forgot how to do it. Here is the problem.\r<BR>\n" );
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document.write( "a pharmacist needs to strengthen a 20% alcohol solution so that it contains 36% alcohol. how much pure alcohol should be added to 240 milliliters of the 20% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #542401 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=542401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a pharmacist needs to strengthen a 20% alcohol solution so that it contains 36% alcohol. how much pure alcohol should be added to 240 milliliters of the 20% solution?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Quantity:: x + y = 240 ml<BR>\n" );
document.write( "Alcohol:: 0.20x + y = 0.36*240<BR>\n" );
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document.write( "Subtract the lower equation <BR>\n" );
document.write( "from the upper equation to get ::<BR>\n" );
document.write( "0.80x = 0.64*240<BR>\n" );
document.write( "x = 192 ml (amt. of 20% solution needed)<BR>\n" );
document.write( "240-x = 48 ml (amt. of pure alcohol needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------------------- </SPAN>\n" );
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