document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75575>Question 75575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please explain how the graph of y=log base 2 of x/7 can be obtained from the graph of y=log base 2 of x. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54240 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please explain how the graph of y=log base 2 of x/7 can be obtained from the graph of y=log base 2 of x.<BR>\n" );
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document.write( "log(base 2)(x/7)= log(base 2)x - log(base 2)7<BR>\n" );
document.write( "So if you have the graph of log(base 2)x<BR>\n" );
document.write( "you can obtain the graph of log(base 2)(x/7) by lowering the graph log(base 2)7,<BR>\n" );
document.write( "that is by subtracting that amount from each of the y values.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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