document.write( "Question 894785: How would I solve for this problem. If the perimeter is 78cm and I have to find the dimentions of the rectangle ?\r
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\n" ); document.write( "\n" ); document.write( " 2x
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\n" ); document.write( "|. | X+3
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Algebra.Com's Answer #542348 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You are attempting to show a rectangle with one dimension 2x and the other dimension x+3;
\n" ); document.write( "and the perimeter is given as 78 cm.\r
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\n" ); document.write( "\n" ); document.write( "\"2%282x%29%2B2%28x%2B3%29=78\", follows formula for perimeter.
\n" ); document.write( "\"2x%2Bx%2B3=39\"
\n" ); document.write( "\"3x=36\"
\n" ); document.write( "\"highlight_green%28x=12%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can now evaluate 2x and x+3.
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