document.write( "Question 894747: Two cars leave towns
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Algebra.Com's Answer #542300 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "Two cars leave towns 600 kilometers apart at the same time and travel toward each other. One car's rate is 18 kilometers per hour less than the other's. If they meet in 4 hours, what is the rate of the slower car?
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document.write( "Let rate of speed of slower car be S
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document.write( "Then rate of speed of faster car = S + 18
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document.write( "Since when they meet, the sum of their individual distances covered will be 600 km, then we can say that: 
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document.write( "4(S) + 4(S + 18) = 600
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document.write( "4S + 4S + 72 = 600
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document.write( "8S = 600 - 72
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document.write( "8S = 528
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document.write( "S, or speed of slower car = , or  km/h
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