document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894749>Question 894749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes Jack 15 hours longer to drain a basement than Jill. If they work together, it takes 4 hours to drain a basement. How long does it take for each person to working alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #542292 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=542292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It takes Jack 15 hours longer to drain a basement than Jill. If they work together, it takes 4 hours to drain a basement. How long does it take for each person to working alone?<BR>\n" );
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document.write( "Draining the basement is the job.<BR>\n" );
document.write( "Jill does it in some number, J, of hours, so she does 1/J per hour.<BR>\n" );
document.write( "Jack does it in J+15 hours, so he does 1/(J+15) per hour.<BR>\n" );
document.write( "Together, they do 1/J + 1/(J+15) per hour, and it takes them 4 hours.<BR>\n" );
document.write( "Together, the do 1/4 of the job.<BR>\n" );
document.write( "---> 1/J + 1/(J+15) = 1/4<BR>\n" );
document.write( "Can you solve for J ?<BR>\n" );
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