document.write( "Question 894637: two trains A and B travels to each other.The distance
\n" ); document.write( "between train A and B is 900 km. Train A start travelling at
\n" ); document.write( "9 AM with speed 150 km/hour and train B start travelling
\n" ); document.write( "at 11 AM with speed 120 km/hour.At what time both trains
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Algebra.Com's Answer #542271 by KMST(5347)\"\" \"About 
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\"t\"= hours since 9 AM.
\n" ); document.write( "For any time not before 9AM , \"t%3E=0\" ,
\n" ); document.write( "train A has traveled \"150%2At\"\"km\" .
\n" ); document.write( "For any time not before 11AM , \"t%3E=2\" ,
\n" ); document.write( "train B has traveled \"120%2A%28t-2%29\"\"km\" .
\n" ); document.write( "If they are to meet at a time such that \"t%3E=2\" ,
\n" ); document.write( "\"150t%2B120%28t-2%29=900\"
\n" ); document.write( "\"150t%2B120t-120%2A2=900\"
\n" ); document.write( "\"150t%2B120t-240=900\"
\n" ); document.write( "\"270t=900%2B240\"
\n" ); document.write( "\"270t=1140\"
\n" ); document.write( "\"t=1140%2F270\"
\n" ); document.write( "\"t=38%2F9\" or \"t=4%262%2F9\"
\n" ); document.write( "\"2%2F9\"\"hour=2%2A60minutes%2F9=40%2F3\"\"minutes=13%261%2F3\"\"minutes\"
\n" ); document.write( "\"1%2F3\"\"minute=60seconds%2F3=20seconds\"
\n" ); document.write( "So the trains will meet 4 hours, 13 minutes and 20 seconds after 9 AM.
\n" ); document.write( "At that time it will be 1:13:20 PM.
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