document.write( "Question 894698: Solve using substitution:
\n" ); document.write( "X=5-y, 3y=3x+1
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Algebra.Com's Answer #542233 by stanbon(75887)\"\" \"About 
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Solve using substitution:
\n" ); document.write( "X=5-y, 3y=3x+1
\n" ); document.write( "--------------
\n" ); document.write( "Substitute for \"x\" and solve for \"y\"::
\n" ); document.write( "3y = 3(5-y) + 1
\n" ); document.write( "3y = 15-3y + 1
\n" ); document.write( "6y = 16
\n" ); document.write( "y = 8/3
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\n" ); document.write( "Solve for \"x\"::
\n" ); document.write( "x = 5 - y
\n" ); document.write( "x = 5 - (8/3)
\n" ); document.write( "x = 7/3
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=================
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