document.write( "Question 75568: Write the equation of the line that passes through point (–6, 7) with a slope of 0.
\n" ); document.write( "A. x = –6
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\n" ); document.write( "C. y = –6
\n" ); document.write( "D. y = 7
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Algebra.Com's Answer #54217 by chitra(359)\"\" \"About 
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The equation of the line that passes through point (–6, 7) with a slope of 0\r
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\n" ); document.write( "\n" ); document.write( "A. x = –6
\n" ); document.write( "B. x = 7
\n" ); document.write( "C. y = –6
\n" ); document.write( "D. y = 7\r
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\n" ); document.write( "\n" ); document.write( "Solution: The general equation of the line is given by: \r
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\n" ); document.write( "\n" ); document.write( "y = mx + c Where m is the slope of the line with b as the constant.\r
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\n" ); document.write( "\n" ); document.write( "Substituting the slope and the given point, we get the value of b. \r
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\n" ); document.write( "\n" ); document.write( "y = (0)x + b \r
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\n" ); document.write( "\n" ); document.write( "7 = (0)(-6) + b \r
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\n" ); document.write( "\n" ); document.write( "7 = b \r
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\n" ); document.write( "\n" ); document.write( "Hence, the equation of the line is given by: \r
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\n" ); document.write( "\n" ); document.write( "y = (0)x + 7 \r
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\n" ); document.write( "\n" ); document.write( "y = 7 is the equation of the line.\r
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