document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894549>Question 894549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the perimeter of the rectangle is 48yd, find its area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #542136 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=542136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 3x\r<BR>\n" );
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document.write( "width = x\r<BR>\n" );
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document.write( "perimeter = 48 yards\r<BR>\n" );
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document.write( "Use P = 2l + 2w\r<BR>\n" );
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document.write( "48 = 2(3x) + 2x\r<BR>\n" );
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document.write( "48 = 6x + 2x\r<BR>\n" );
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document.write( "48 = 8x\r<BR>\n" );
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document.write( "48/8 = x\r<BR>\n" );
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document.write( "6 = x\r<BR>\n" );
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document.write( "This tells me that the width is 6 yards and the length is 18 yards. \r<BR>\n" );
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document.write( "Use A = length times width to find the area.\r<BR>\n" );
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document.write( "A = 3x times x\r<BR>\n" );
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document.write( "A = 3(6)(6)\r<BR>\n" );
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document.write( "A = 18 times 6\r<BR>\n" );
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document.write( "A = 108\r<BR>\n" );
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document.write( "The area is 108 yards^2.\r<BR>\n" );
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