document.write( "Question 894558: If a new operation called # is defined as a # b = 2 (a-3b) then find -7#5 \n" ); document.write( "
Algebra.Com's Answer #542132 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
Just follow the formula. You have a symbolized definition for the # operation between two numbers, so just apply it.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What if you wanted x#y? this would be 2(x-3y) and you could continue into 2x-6y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now you should understand plainly what to do.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Your second expression to be answered seem ambiguous.
\n" ); document.write( "-7#5 either means (-7)#5 or -(7#5). Seeing through before doing the steps is difficult.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First way,
\n" ); document.write( "2((-7)-3*5)
\n" ); document.write( "2(-7-15)
\n" ); document.write( "2*(-22)
\n" ); document.write( "-44\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Second way,
\n" ); document.write( "-(2(7-3*5))
\n" ); document.write( "-(2(7-15)
\n" ); document.write( "-2(-8)
\n" ); document.write( "16\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "These ways are not identical. Decide which way you want to begin with for that second example to be solved and then choose the steps accordingly (although I just did both of these).
\n" ); document.write( "
\n" );