document.write( "Question 894558: If a new operation called # is defined as a # b = 2 (a-3b) then find -7#5 \n" ); document.write( "
Algebra.Com's Answer #542132 by josgarithmetic(39621)![]() ![]() ![]() You can put this solution on YOUR website! Just follow the formula. You have a symbolized definition for the # operation between two numbers, so just apply it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What if you wanted x#y? this would be 2(x-3y) and you could continue into 2x-6y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you should understand plainly what to do.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your second expression to be answered seem ambiguous. \n" ); document.write( "-7#5 either means (-7)#5 or -(7#5). Seeing through before doing the steps is difficult.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First way, \n" ); document.write( "2((-7)-3*5) \n" ); document.write( "2(-7-15) \n" ); document.write( "2*(-22) \n" ); document.write( "-44\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second way, \n" ); document.write( "-(2(7-3*5)) \n" ); document.write( "-(2(7-15) \n" ); document.write( "-2(-8) \n" ); document.write( "16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These ways are not identical. Decide which way you want to begin with for that second example to be solved and then choose the steps accordingly (although I just did both of these). \n" ); document.write( " |