document.write( "Question 894463: In fourteen years time a mother will be twice as old as her son.Four years ago the sum of their ages was 30 years.Find how old the mother was when the son was born. \n" ); document.write( "

Algebra.Com's Answer #542067 by mananth(16946) $\"\"$ $\"About$

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In fourteen years time a mother will be twice as old as her son.Four years ago the sum of their ages was 30 years.Find how old the mother was when the son was born.\r
\n" ); document.write( "\n" ); document.write( "let mother be x years and son be y years now\r
\n" ); document.write( "\n" ); document.write( "After 14 years
\n" ); document.write( "(x+14)=2(y+14)\r
\n" ); document.write( "\n" ); document.write( "x+14=2y+28
\n" ); document.write( "x-2y=14.......................(1)\r
\n" ); document.write( "\n" ); document.write( "4 years ago
\n" ); document.write( "(x-4) +(y-4) =30\r
\n" ); document.write( "\n" ); document.write( "x+Y-8=30
\n" ); document.write( "x+y = 38.......................(2)\r
\n" ); document.write( "\n" ); document.write( "subtract (2) from (1)\r
\n" ); document.write( "\n" ); document.write( "-3y=-24
\n" ); document.write( "y=8\r
\n" ); document.write( "\n" ); document.write( "Therefore x=30 because x+y=38\r
\n" ); document.write( "\n" ); document.write( "Son was born 8 years ago
\n" ); document.write( "so mother was 30-8 = 22 years then\r
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