document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894320>Question 894320</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary.  The measure of one is four-fifths the measure of the other.  Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #542013 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=542013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary.<BR>\n" );
document.write( "A + B  = 180<BR>\n" );
document.write( " The measure of one is four-fifths the measure of the other.<BR>\n" );
document.write( "B = .8A<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "A + .8A = 180<BR>\n" );
document.write( "1.8A = 180<BR>\n" );
document.write( "A = 180/1.8<BR>\n" );
document.write( "A = 100 degrees<BR>\n" );
document.write( ":<BR>\n" );
document.write( " Find the measure of each angle. I'll let you find B </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );