document.write( "Question 894222: Solve the equation. \r
\n" ); document.write( "\n" ); document.write( "sqr rt ^ 38x+647 +17= x+35 \r
\n" ); document.write( "\n" ); document.write( "The solution set is { }
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Algebra.Com's Answer #541929 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%2838x%2B647%29+%2B17=+x%2B35+\"
\n" ); document.write( "\"sqrt%2838x%2B647%29=x%2B18\"
\n" ); document.write( "\"38x%2B647=%28x%2B18%29%5E2\"
\n" ); document.write( "\"38x%2B647=x%5E2%2B36x%2B324\"
\n" ); document.write( "\"x%5E2-2x-323=0\"
\n" ); document.write( "\"%28x-19%29%28x%2B17%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"x-19=0\"
\n" ); document.write( "\"x=19\"
\n" ); document.write( "and
\n" ); document.write( "\"x%2B17=0\"
\n" ); document.write( "\"x=-17\"
\n" ); document.write( "Now go back to the original equation and plug in the values and make
\n" ); document.write( "sure neither of the solutions are extraneous solutions (don't solve the equation).
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