document.write( "Question 894310: About 77% of the nurses wear their uniform in a certain hospital. If four nurses are randomly selected, find the probability that at least one of the nurses does not wear a uniform.\r
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document.write( "I tried solving this problem by:\r
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document.write( "P(at least 1 out of 4 wears uniform) = 1 - P(no one wears uniform)
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document.write( "P(at least 1 out of 4 wears uniform) = 1 - (0.23^4)
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document.write( "P(at least 1 out of 4 wears uniform) = 1 - 0.00279841
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document.write( "P(at least 1 out of 4 wears uniform) = 0.99720159
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document.write( "P(at least 1 out of 4 wears uniform) = 99.7%\r
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document.write( "AM I CORRECT? IF NOT, KINDLY IMPROVE MY SOLUTION. THANKS. \n" );
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Algebra.Com's Answer #541921 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i believe you are correct. \n" ); document.write( "p = .77 = probability that a nurse wears a uniform. \n" ); document.write( "q = 1 - .77 = .23 = probability that a nurse doesn't wear a uniform. \n" ); document.write( "p(at least 1 wears a uniform) is equal to 1 - p(none of them wears a uniform). \n" ); document.write( "the formula for p(x >= 1) is 1 - p(x = 0) = 1 - C(4,0) * .77^0 * .23^(4-0) \n" ); document.write( "this becomes 1 - 1 * 1 * .23^4 which becomes: \n" ); document.write( "1 - .23^4 which becomes: \n" ); document.write( "1 - .00279841 which becomes: \n" ); document.write( ".99720159 which becomes: \n" ); document.write( "99.7% if you are rounding to the nearest tenth of a percent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution looks good. \n" ); document.write( "you did all the right steps. \n" ); document.write( "i get the same answer as you. \n" ); document.write( " |