document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894306>Question 894306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ten years from now,A will be twice as old B and five years ago,A was three times as old as B. what are the present age of A and B. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541907 by </B><A HREF=/tutors/aboutme.mpl?userid=mark_henrhiz><B>mark_henrhiz(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mark_henrhiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mark_henrhiz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> their ages 10 years from now are:\r<BR>\n" );
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document.write( "A+10<BR>\n" );
document.write( "B+10\r<BR>\n" );
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document.write( "Their ages 5 years ago are:\r<BR>\n" );
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document.write( "A-5<BR>\n" );
document.write( "B-5\r<BR>\n" );
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document.write( "Translating to equations:\r<BR>\n" );
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document.write( "A+10 = 2(B+10)<BR>\n" );
document.write( "A+10 = 2B+20        <BR>\n" );
document.write( "A-2B = 20-10        <BR>\n" );
document.write( "<b>A-2B = 10</b>    FIRST EQUATION\r<BR>\n" );
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document.write( "        <BR>\n" );
document.write( "A-5  = 3(B-5)<BR>\n" );
document.write( "A-5  = 3B-15<BR>\n" );
document.write( "A-3B = -15+5<BR>\n" );
document.write( "<b>A-3B  = -10</b>    SECOND EQUATION\r<BR>\n" );
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document.write( "THUS,\r<BR>\n" );
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document.write( "A-2B =  10<BR>\n" );
document.write( "A-3B = -10\r<BR>\n" );
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document.write( "WE CAN SOLVE THIS EITHER BY ADDITION METHOD OR SUBSTITUTION METHOD.\r<BR>\n" );
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document.write( "THROUGH ADDITION METHOD\r<BR>\n" );
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document.write( "(A-2B = 10)-1   WE MULTIPLY -1 TO THE FIRST EQUATION TO GET RID OF \"A\"<BR>\n" );
document.write( "+<u>(A-3B =-10)</u>       IN ORDER TO FIND THE VALUE OF \"B\"\r<BR>\n" );
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document.write( "HENCE,\r<BR>\n" );
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document.write( "-A+2B = -10<BR>\n" );
document.write( "+<u>A-3B = -10</u>    WE ADD<BR>\n" );
document.write( "   -B = -20    WE DIVIDE BOTH SIDES WITH -1<BR>\n" );
document.write( "    B = 20\r<BR>\n" );
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document.write( "WE CAN NOW SOLVE FOR \"A\" USING EITHER OF THE TWO EQUATIONS\r<BR>\n" );
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document.write( "A - 2B = 10<BR>\n" );
document.write( "A-2*20 = 10   SUBSTITUTE 20<BR>\n" );
document.write( "A-40   = 10<BR>\n" );
document.write( "    A  = 10 + 40<BR>\n" );
document.write( "    A  = 50\r<BR>\n" );
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document.write( "THEREFORE, \"A\" IS 50 YEARS OLD WHILE \"B\" IS 20 YEARS OLD NOW.<BR>\n" );
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document.write( " </SPAN>\n" );
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