document.write( "Question 894282: You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 mph your friend rides a bike at 11 mph.\r
\n" ); document.write( "\n" ); document.write( "A. How long after you leave will you meet?
\n" ); document.write( "B. suppose your friend travels at a rate of 12 mph how much sooner will you meet? How far from home will each of you be?
\n" ); document.write( "

Algebra.Com's Answer #541904 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 mph your friend rides a bike at 11 mph.\r
\n" ); document.write( "\n" ); document.write( "A. How long after you leave will you meet?
\n" ); document.write( "B. suppose your friend travels at a rate of 12 mph how much sooner will you meet? How far from home will each of you be?
\n" ); document.write( "

\n" ); document.write( "A.
\n" ); document.write( "We will meet: \"highlight_green%284%2F5%29\" hour, or \"highlight_green%2848%29\" minutes after leaving our respective destinations
\n" ); document.write( "B.
\n" ); document.write( "With friend traveling at 12 mph, the meeting will take \"3%2F4%29\" hour or \"45\" minutes.
\n" ); document.write( "Therefore, we will meet \"highlight_green%283%29\" (48 - 45) minutes earlier
\n" ); document.write( "C.
\n" ); document.write( "With friend traveling at 12 mph, we will meet \"highlight_green%283%29\" miles from my home, which is
\n" ); document.write( "\"highlight_green%289%29\" miles from the friend's home.
\n" ); document.write( "You can do the check!! \r
\n" ); document.write( "\n" ); document.write( "If you need a complete and detailed solution, let me know!!\r
\n" ); document.write( "\n" ); document.write( "Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com.
\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. \r
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