document.write( "Question 894282: You and your friend live 12 miles apart. You leave home at the same time and travel toward each other. You walk at a rate of 4 mph your friend rides a bike at 11 mph.\r
\n" ); document.write( "\n" ); document.write( "A. How long after you leave will you meet?
\n" ); document.write( "B. suppose your friend travels at a rate of 12 mph how much sooner will you meet? How far from home will each of you be?
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Algebra.Com's Answer #541902 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Part A, approach rate is \"4%2B11=15\" mph.
\n" ); document.write( "\"15%28miles%2Fhour%29%28t%29%28hours%29=12%2Amiles\"
\n" ); document.write( "\"15t=12\"
\n" ); document.write( "\"t=12%2F15\"
\n" ); document.write( "\"highlight%28t=4%2F5%29\" hour
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