document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10267>Question 10267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Heavy cream, which is 30% butterfat, and lowfat milk, which is 2% butterfat, are added together to make 100 gallons of regular milk, which is 4% butterfat. How much of cream and low fat milk should be used?\r<BR>\n" );
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document.write( "This is what I have set up (i don't know if it's right...):<BR>\n" );
document.write( ".30x + .02y = .04(100) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5419 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is correct, except that if you have two variables you will need two equations.  The other equation (the easy one!) was x+ y = 100, from which you might want to solve for y = 100-x, and substitute into the other equation to get:\r<BR>\n" );
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document.write( ".30x + .02(100-x) = .04(100)<BR>\n" );
document.write( ".30x + 2 - .02x = 4<BR>\n" );
document.write( ".28x = 2<BR>\n" );
document.write( "x = 2/.28 = 50/7 or approximately 7.14 gallons of cream<BR>\n" );
document.write( "100-x = 92 6/7 or approximately 92.86 gallons of 2%\r<BR>\n" );
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document.write( "R^2 at SCC  </SPAN>\n" );
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