document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75495>Question 75495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a swimming pool has the shape of a semi-circle. if the area is 308 square meters, find the perimeter of the pool.[pi=22/7]   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54187 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA OF A CIRCLE=PI*R^2<BR>\n" );
document.write( "308=(22/7*R^2)/2 CROSS MULTIPLY<BR>\n" );
document.write( "(22/7*R^2)=616<BR>\n" );
document.write( "22R^2/7=616 CROSS MULTIPLY AGAIN<BR>\n" );
document.write( "22R^2=616*7<BR>\n" );
document.write( "22R^2=4312<BR>\n" );
document.write( "R^2=4312/22<BR>\n" );
document.write( "R^2=196<BR>\n" );
document.write( "R=14 METERS IS THE RADIUS OF THE POOL.<BR>\n" );
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