document.write( "Question 894263: three men do a job in 12 days.Two of the men work twice ass fast as third.How long will it take one of the faster men. \n" ); document.write( "
Algebra.Com's Answer #541868 by ankor@dixie-net.com(22740)\"\" \"About 
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three men do a job in 12 days.
\n" ); document.write( "Two of the men work twice as fast as third.
\n" ); document.write( "How long will it take one of the faster men.
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\n" ); document.write( "let t = time required by one of the faster men to do the job alone
\n" ); document.write( "then
\n" ); document.write( "2t = time required by the slower guy
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "A shared work equation
\n" ); document.write( "\"12%2Ft\" + \"12%2Ft\" + \"12%2F%282t%29\" = 1
\n" ); document.write( "multiply thru by 2t
\n" ); document.write( "2(12) + 2(12) + 12 = 2t
\n" ); document.write( "24 + 24 + 12 = 2t
\n" ); document.write( "60 = 2t
\n" ); document.write( "t - 60/2
\n" ); document.write( "t = 30 days for one of the faster guys to do the job
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\n" ); document.write( "you can check this for yourself
\n" ); document.write( "\"12%2F30\" + \"12%2F30\" + \"12%2F%2860%29\" =
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