document.write( "Question 894263: three men do a job in 12 days.Two of the men work twice ass fast as third.How long will it take one of the faster men. \n" ); document.write( "
Algebra.Com's Answer #541868 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! three men do a job in 12 days. \n" ); document.write( "Two of the men work twice as fast as third. \n" ); document.write( "How long will it take one of the faster men. \n" ); document.write( ": \n" ); document.write( "let t = time required by one of the faster men to do the job alone \n" ); document.write( "then \n" ); document.write( "2t = time required by the slower guy \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "A shared work equation \n" ); document.write( " \n" ); document.write( "multiply thru by 2t \n" ); document.write( "2(12) + 2(12) + 12 = 2t \n" ); document.write( "24 + 24 + 12 = 2t \n" ); document.write( "60 = 2t \n" ); document.write( "t - 60/2 \n" ); document.write( "t = 30 days for one of the faster guys to do the job \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "you can check this for yourself \n" ); document.write( " |