document.write( "Question 894166: Write the equation of the circle in standard form and give the center and radius.\r
\n" ); document.write( "\n" ); document.write( "4x^2+4y^2-4x-8y-1=0
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Algebra.Com's Answer #541811 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
I will only take this part of the way and you can finish it:\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2-4x%2B4y%5E2-8y=1\"
\n" ); document.write( "\"4%28x%5E2-x%29%2B4%28y%5E2-2y%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "You need to Complete The Squares.
\n" ); document.write( "The term for x is \"%28-1%2F2%29%5E2=1%2F4\"
\n" ); document.write( "The term for y is \"%28-2%2F2%29%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%28x%5E2-x%2B1%2F4%29%2B4%28y%5E2-2y%2B1%29=1%2B4%281%2F4%29%2B4%2A1\", note that is equivalent to adding the two square terms to both sides of the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"4%28x-1%2F2%29%5E2%2B4%28y-1%29%5E2=1%2B1%2B4\"
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\n" ); document.write( "Now, you continue and finish.
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