document.write( "Question 894137: if you have 8 teams, what are the odds of two people joining a league being drafted on the same team
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Algebra.Com's Answer #541787 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i believe the probability is going to be 1/8. \n" ); document.write( "here's why. \n" ); document.write( "assume only 3 teams. \n" ); document.write( "assume the teams are ABC \n" ); document.write( "you have 2 people, each of which can land on any of the teams. \n" ); document.write( "the possible pairings you can get will be 3*3 = 9 \n" ); document.write( "person 1 gets the first letter \n" ); document.write( "person 2 gets the second letter. \n" ); document.write( "the letter designates the team. \n" ); document.write( "the possible pairings are: \n" ); document.write( "AA ***** \n" ); document.write( "AB \n" ); document.write( "AC \n" ); document.write( "BA \n" ); document.write( "BB ***** \n" ); document.write( "BC \n" ); document.write( "CA \n" ); document.write( "CB \n" ); document.write( "CC *****\r \n" ); document.write( "\n" ); document.write( "out of the 9 possible pairings there are 3 pairings where person 1 and person 2 are on the same team.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "remember. \n" ); document.write( "the first column represents the team that person 1 gets. \n" ); document.write( "the second column represents the team that person 2 gets.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 out of 9 is the same as 1 out of 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use that logic with the 8 teams and you get the probability that they will be on the same team is 8/64 which is equal to 1/8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a sample of a subset of what that will look like is shown below: \n" ); document.write( "the teams are ABCDEFGH \n" ); document.write( "the possible pairings are: \n" ); document.write( "AA ***** \n" ); document.write( "AB \n" ); document.write( "AC \n" ); document.write( "AD \n" ); document.write( "AE \n" ); document.write( "AF \n" ); document.write( "AG \n" ); document.write( "AH \n" ); document.write( "BA \n" ); document.write( "BB ***** \n" ); document.write( "BC \n" ); document.write( "BD \n" ); document.write( "BE \n" ); document.write( "BF \n" ); document.write( "BG \n" ); document.write( "BH \n" ); document.write( "etc 8 times in all.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in the first set of 8, 1 pairing had both persons on the same team (team A). \n" ); document.write( "in the second set of 8, 1 pairing had both persons on the same team (team B).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this will occur 8 times out of 64 which results in 1 out of 8 which give you a probability of 1/8.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |