document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=894134>Question 894134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tan theta=2 find the five other trigonometric function values<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541779 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> tan(theta) = 2<BR>\n" );
document.write( "this means that opposite divided by adjacent is equal to 2.<BR>\n" );
document.write( "this can occur if opposite = 2 and adjacent = 1<BR>\n" );
document.write( "this would make hypotenuse equal to sqrt(2^2 + 1^2) = sqrt(5).<BR>\n" );
document.write( "your other functions would then be:\r<BR>\n" );
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document.write( "sin (theta) = opp/hyp = 2/sqrt(5) = 2*sqrt(5)/5\r<BR>\n" );
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document.write( "cos(theta) = adj/hyp = 1/sqrt(5) = sqrt(5)/5\r<BR>\n" );
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document.write( "tan(theta) = opp/adj = 2/1 = 2\r<BR>\n" );
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document.write( "cot(theta) = adj/opp = 1/2\r<BR>\n" );
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document.write( "sec(theta) = hyp/adj = sqrt(5)/1 = sqrt(5)\r<BR>\n" );
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document.write( "csc(theta) = hyp/opp = sqrt(5)/2\r<BR>\n" );
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