document.write( "Question 893993: A water tank has the shape of a cone with the vertex down. The tank is 10 m high and has a base radius of 3 m. When the water in the tank is 5 m deep, what is the area of the surface of the water at that instant? (Hint: make a sketch and set up similar triangles.)\r
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Algebra.Com's Answer #541688 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This really works better with a picture.\r
\n" ); document.write( "\n" ); document.write( "Top diameter for the tank is 3 m, and distance top to bottom of the tank is 10 m.
\n" ); document.write( "The ratio of diameter to height, \"d%2Fh=3%2F10\". This is using d for DIAMETER and h for HEIGHT or DEPTH. You can recognize similar triangles if this helps.\r
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\n" ); document.write( "\n" ); document.write( "If you want the surface area of the top of the liquid when the filled depth is 5 m, then:\r
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\n" ); document.write( "\n" ); document.write( "\"d=h%283%2F10%29\"
\n" ); document.write( "\"d=5%283%2F10%29\"
\n" ); document.write( "\"d=3%2F2\"
\n" ); document.write( "Know that half of diameter is radius; so the radius at that depth is \"r=d%2F2=3%2F2%2F2=3%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Now to get the value for this surface area of the liquid at the top of this depth, \"highlight%28pi%2A%283%2F4%29%5E2%29\".
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