document.write( "Question 893993: A water tank has the shape of a cone with the vertex down. The tank is 10 m high and has a base radius of 3 m. When the water in the tank is 5 m deep, what is the area of the surface of the water at that instant? (Hint: make a sketch and set up similar triangles.)\r
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Algebra.Com's Answer #541688 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! This really works better with a picture.\r \n" ); document.write( "\n" ); document.write( "Top diameter for the tank is 3 m, and distance top to bottom of the tank is 10 m. \n" ); document.write( "The ratio of diameter to height, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want the surface area of the top of the liquid when the filled depth is 5 m, then:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Know that half of diameter is radius; so the radius at that depth is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now to get the value for this surface area of the liquid at the top of this depth, |