document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=891473>Question 891473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A can do 1/3 of a work in 5 days and B can do 2/5 of the work in 10 days.  How many days both A and B together can do the work? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541621 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/3 of a job in 5 days works out to the whole job in 15 days<BR>\n" );
document.write( "2/5 of a job in 10 days  works out to the whole job in 25 days\r<BR>\n" );
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document.write( "1/15+1/25=1/x<BR>\n" );
document.write( "5/75+3/75=1/x<BR>\n" );
document.write( "8/75=1/x<BR>\n" );
document.write( "x=75/8=9.378 days = 9 days and 3 hours assuming an 8 hour day\r<BR>\n" );
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