document.write( "Question 893870: 1+(1/x^2)=(3/x)
\n" ); document.write( "what are the solutions to the equation?
\n" ); document.write( "A. x=(3/2)+(square root of 5/2); x=(3/2)-(square root of 5/2)
\n" ); document.write( "B.x=(3)+(square root of 5/2); x=(3)-(square root of 5/2)
\n" ); document.write( "C.x=(3/2)+(square root of 13/2); x=(3/2)-(square root of 13/2)
\n" ); document.write( "D.x=(3)+(square root of 13/2); x=(3)-(square root of 13/2)
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Algebra.Com's Answer #541594 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your equation is 1 + (1/x^2) = 3/x)\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the equation by x^2 to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 1 = 3x\r
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\n" ); document.write( "\n" ); document.write( "subtract 3x from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 3x + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "use the quadratic formula to solve for x.\r
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\n" ); document.write( "\n" ); document.write( "you will get x = (3 +/- sqrt(5)) / 2\r
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\n" ); document.write( "\n" ); document.write( "this is equivalent to x = 3/2 +/- sqrt(5)/2\r
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\n" ); document.write( "\n" ); document.write( "that should be selection a.\r
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\n" ); document.write( "\n" ); document.write( "the quadratic formula is:\r
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document.write( "x =                -b +/- sqrt(b^2 - 4ac)\r\n" );
document.write( "                -------------------------------\r\n" );
document.write( "                             2a\r\n" );
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\n" ); document.write( "\n" ); document.write( "your formula has to be in the standard form of ax^2 + bx + c = 0
\n" ); document.write( "your formula is x^2 - 3x + 1 = 0
\n" ); document.write( "you get:
\n" ); document.write( "a = 1
\n" ); document.write( "b = -3
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\n" ); document.write( "\n" ); document.write( "replace a and b and c in the formula and solve for x.\r
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