document.write( "Question 893693: Find the dimensions of the rectangle if the width is 3 feet less than the length and the area is 40 ft^2? \n" ); document.write( "

Algebra.Com's Answer #541575 by Fombitz(32388) $\"\"$ $\"About$

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For a rectangle,
\n" ); document.write( " $\"A=L%2AW\"$
\n" ); document.write( "In this case,
\n" ); document.write( " $\"W=L-3\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"L%2AW=40\"$
\n" ); document.write( " $\"L%28L-3%29=40\"$
\n" ); document.write( " $\"L%5E2-3L=40\"$
\n" ); document.write( " $\"L%5E2-3L-40=0\"$
\n" ); document.write( " $\"%28L-8%29%28L%2B5%29=0\"$
\n" ); document.write( "Two solutions however only the positive solution makes sense here.
\n" ); document.write( " $\"L-8=0\"$
\n" ); document.write( " $\"L=8\"$ $\"ft\"$
\n" ); document.write( "Then,
\n" ); document.write( " $\"W=8-3\"$
\n" ); document.write( " $\"W=5\"$ $\"ft\"$ \n" ); document.write( "

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