document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=893847>Question 893847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cards are drawn one after another at random from a standard deck of cards. In how many ways can a 7 and then a club be drawn if the cards are drawn without replacement?(please provide explanation for solution) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541547 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the first card (7), there are 4 ways to choose it since there are four 7's in the deck.<BR>\n" );
document.write( "For the second card, there are 13 ways to choose if the 7 is not a club and there are 12 ways to choose if the 7 is a club since the first card is not replaced. <BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=N%5B2%5D=4%2A12=48 ALIGN=MIDDLE  ALT=\"N%5B2%5D=4%2A12=48\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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