document.write( "Question 893825: A quadratic equation has an x intercept at 2.5 and 5 and a y value y=-2.25. Use any valid method to calulate the equation of the quadratic in the form y=ax^2 +bx+c \n" ); document.write( "
Algebra.Com's Answer #541525 by lwsshak3(11628)\"\" \"About 
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A quadratic equation has an x intercept at 2.5 and 5 and a y value y=-2.25. Use any valid method to calulate the equation of the quadratic in the form y=ax^2 +bx+c
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\n" ); document.write( "(x-2.5)(x-5)=-2.25
\n" ); document.write( "x^2-7.25x+12.5=-2.25
\n" ); document.write( "x^2-7.25x+14.75=0
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