document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=893809>Question 893809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A vehicle starts traveling from city A towards city B. It maintains a speed of 45 miles per hour. Another vehicle starts the same trip 45 minutes later going 70 miles per hour. Where (a distance from city A) will the faster vehicle take over the slower one. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541519 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> vehicle A travels .75 *45=33.75 miles in 45 minutes before Vehicle B has started.<BR>\n" );
document.write( "Vehicle B is going 70-45 =25 mph faster than vehicle A<BR>\n" );
document.write( "so it will take B 33.75/25=1.35 hours to catch up<BR>\n" );
document.write( "in 1.35 hours b goes 70*1.35=94.5 miles\r<BR>\n" );
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