document.write( "Question 893802: find four consecutive integers such that twice the sum of the first, second, and fourth is 40 less than 3 times the opposite of the third \n" ); document.write( "

Algebra.Com's Answer #541505 by josgarithmetic(39618) $\"\"$ $\"About$

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The integers, n, n+1, n+2, n+3.\r
\n" ); document.write( "\n" ); document.write( " $\"2%28n%2B%28n%2B1%29%2B%28n%2B3%29%29=-40%2B3%28-%28n%2B2%29%29\"$ , description transcribed into equation;\r
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\n" ); document.write( "\n" ); document.write( " $\"2%283n%2B4%29=-40-3%28n%2B2%29\"$
\n" ); document.write( " $\"6n%2B8=-40-3n-6\"$
\n" ); document.write( " $\"9n%2B8=-40-6\"$
\n" ); document.write( " $\"9n%2B8=-46\"$
\n" ); document.write( " $\"9n=-46-8\"$
\n" ); document.write( " $\"9n=-54\"$
\n" ); document.write( " $\"n=-54%2F9\"$
\n" ); document.write( " $\"highlight%28n=-6%29\"$ , and you can find next ones: -5, -4, -3.
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