document.write( "Question 893760: Find the vertex, focus, and directix of the parabola\r
\n" ); document.write( "\n" ); document.write( "(x+2)^2 = 8(y-3)
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Algebra.Com's Answer #541502 by lwsshak3(11628)\"\" \"About 
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Find the vertex, focus, and directrix of the parabola
\n" ); document.write( "(x+2)^2 = 8(y-3)
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\n" ); document.write( "This is an equation of parabola that opens upwards:
\n" ); document.write( "Its basic form of equation: (x-h)^2=4p(y-k)^2, (h,k)=coordinates of vertex
\n" ); document.write( "For given problem:
\n" ); document.write( "vertex:(-2,3)
\n" ); document.write( "axis of symmetry: x=-2
\n" ); document.write( "4p=8
\n" ); document.write( "p=2
\n" ); document.write( "focus: (-2,5) (p-units above vertex on the axis of symmetry)
\n" ); document.write( "directrix: y=1 (p-units below vertex on the axis of symmetry)
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