document.write( "Question 893713: how to solve the square root of the quantity three x minus two is less than or equal to two. \n" ); document.write( "
Algebra.Com's Answer #541436 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%283x-2%29%3C=2\"
\n" ); document.write( "\"3x-2%3C=4\"
\n" ); document.write( "\"3x%3C=6\"
\n" ); document.write( "\"x%3C=2\"
\n" ); document.write( "However the argument of the square root function must be greater than or equal to zero.
\n" ); document.write( "\"3x-2%3E=0\"
\n" ); document.write( "\"3x%3E=2\"
\n" ); document.write( "\"x%3E=2%2F3\"
\n" ); document.write( "So then,
\n" ); document.write( "\"2%2F3%3C=x%3C=2\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );