document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=893633>Question 893633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> alex collects dimes and quarters. he has 31.70 total. if he has 5 fewer dimes than quarters, how many of each does he have </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541408 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> alex collects dimes and quarters. he has 31.70 total. if he has 5 fewer dimes than quarters, how many of each does he have<BR>\n" );
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document.write( "Using imagination and cleverness:<BR>\n" );
document.write( "If he had 5 more dimes, it would be 32.20 total.<BR>\n" );
document.write( "1Q and 1D = 35 cents.<BR>\n" );
document.write( "3220/35 = 92 pairs of coins.<BR>\n" );
document.write( "So he has 92 Q's and 87 D's<BR>\n" );
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document.write( "The hard way:<BR>\n" );
document.write( "10D + 25(D+5) = 3170<BR>\n" );
document.write( "35D + 125 = 3170<BR>\n" );
document.write( "35D = 3045<BR>\n" );
document.write( "D = 87<BR>\n" );
document.write( "Q = 92 </SPAN>\n" );
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