document.write( "Question 75436: can you please help me Factor the Following Quadratic:\r
\n" ); document.write( "\n" ); document.write( " 7a^2 + 17a + 6 \n" ); document.write( "

Algebra.Com's Answer #54136 by Earlsdon(6294) $\"\"$ $\"About$

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Factor:
\n" ); document.write( " $\"7a%5E2%2B17a%2B6\"$ The factors will have the form: (?a+m)(?a+n)
\n" ); document.write( "First, what are the possible factors of the first term $\"7a%5E2\"$ ?
\n" ); document.write( "The only possibility here is: $\"7a%5E2+=+7a%2Aa\"$ so you can start with:
\n" ); document.write( " $\"%287a%2Bm%29%28a%2Bn%29\"$
\n" ); document.write( "The m and n must meet the following requirements:
\n" ); document.write( "m*n = 6 This is the last term of the trinomial.
\n" ); document.write( "The possibilities are:
\n" ); document.write( "m = 3 and n = 2
\n" ); document.write( "m = 1 and n = 6
\n" ); document.write( "Let's try the first set.
\n" ); document.write( " $\"%287a%2B3%29%28a%2B2%29\"$ Using the FOIL method, multiply these factors.
\n" ); document.write( " $\"%287a%2B3%29%28a%2B2%29+=+7a%5E2%2B14a%2B3a%2B6\"$ Simplify to get: $\"7a%5E2%2B17a%2B6\"$ which is the original trinomial.
\n" ); document.write( "The factors are: $\"%287a%2B3%29%28a%2B2%29\"$ \n" ); document.write( "

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