document.write( "Question 893526: Find the area of a rectangle whose length is five less than four times its width and whose perimeter is thirty more than six times its width.
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Algebra.Com's Answer #541348 by MathTherapy(10552) $\"\"$ $\"About$

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Find the area of a rectangle whose length is five less than four times its width and whose perimeter is thirty more than six times its width.
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document.write( "Let width be W
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document.write( "Then length = 4W - 5
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document.write( "Perimeter = 2W + 2L, or 2W + 2(4W - 5), or 2W + 8W - 10, or 10W - 10
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document.write( "With given perimeter, we have: 10W - 10 = 6W + 30
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document.write( "10W - 6W = 30 + 10
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document.write( "4W = 40
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document.write( "W, or with = , or 10
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document.write( "Length:  4(10) - 5, or 40 - 5, or 35
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document.write( "Area:    10(35), or  \n" );
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