document.write( "Question 893526: Find the area of a rectangle whose length is five less than four times its width and whose perimeter is thirty more than six times its width.
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Algebra.Com's Answer #541330 by josgarithmetic(39617)\"\" \"About 
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w and L for width and length, in that order.\r
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\n" ); document.write( "\n" ); document.write( "L=-5+4w and 2w+2L=30+6w. These are just the symbolism translations of the description.\r
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\n" ); document.write( "\n" ); document.write( "The perimeter description equation simplifies to\"w%2BL=15%2B3w\",
\n" ); document.write( "\"L=15%2B2w\"
\n" ); document.write( "\"2w-L=-15\"
\n" ); document.write( "\"L-2w=15\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting for L,
\n" ); document.write( "\"%284w-5%29-2w=15\"
\n" ); document.write( "\"2w-5=15\"
\n" ); document.write( "\"2w=20\"
\n" ); document.write( "\"highlight%28w=10%29\"
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\n" ); document.write( "Now find L.
\n" ); document.write( "\"L=4w-5\"
\n" ); document.write( "\"L=4%2A20-5\"
\n" ); document.write( "\"highlight%28L=75%29\"\r
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\n" ); document.write( "\n" ); document.write( "Area is wL.
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