document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75432>Question 75432</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor the GCF 48x^2y+20xz+12xy+5z </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54132 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rearrange (re-group)the terms so that terms with common factors are together]<BR>\n" );
document.write( "48x^2y+20xz+12xy+5z<BR>\n" );
document.write( "(48x^2y + 12xy) + (20xz + 5z)<BR>\n" );
document.write( "12xy(48x^2y + 12xy) + 5z(20xz + 5z) [factor out the GCF amongst each group]\r<BR>\n" );
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document.write( "12xy(48x^2y/12xy + 12xy/12xy) + 5z(20xz/5z + 5z/5z) [divide each term by its GCF]<BR>\n" );
document.write( "12xy(4x+1)+5z(4x+1) [re-factor out the next GCF ((4x+1)<BR>\n" );
document.write( "(12xy+5z)(4x+1)\r<BR>\n" );
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document.write( ".<BR>\n" );
document.write( "Check by multiplying the factors.  You should get the original expression.<BR>\n" );
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