document.write( "Question 893391: Maria can paddle her canoe 2 miles upstream against the current in the same time it would take her to paddle 6 miles downstream. Maria can paddle 2mph in still water. What is the speed of the current?\r
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Algebra.Com's Answer #541288 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Maria can paddle her canoe 2 miles upstream against the current in the same time it would take her to paddle 6 miles downstream.
\n" ); document.write( " Maria can paddle 2mph in still water.
\n" ); document.write( " What is the speed of the current?
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\n" ); document.write( "let c = the rate of the current
\n" ); document.write( "then
\n" ); document.write( "(2-c) = effective speed upstream
\n" ); document.write( "and
\n" ); document.write( "(2+c) = effective speed downstream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "Two mi upstr time = six mi downstr time
\n" ); document.write( " $\"2%2F%28%282-c%29%29\"$ = $\"6%2F%28%282%2Bc%29%29\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "2(2+c) = 6(2-c)
\n" ); document.write( "4 + 2c = 12 - 6c
\n" ); document.write( "2c + 6c = 12 - 4
\n" ); document.write( "8c = 8
\n" ); document.write( "c = 1 mph is the current
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\n" ); document.write( "Check this, find the time each way,
\n" ); document.write( "effective speed down: 2 + 1 = 3 mph
\n" ); document.write( "effective speed up: 2 - 1 = 1 mph
\n" ); document.write( "6/3 = 2 hr
\n" ); document.write( "2/1 = 2 hrs \n" ); document.write( "

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